Question

A car accelerates uniformly from rest to 0.6m/s^2 for 11 seconds and continues at the maximum speed attained. What is the time taken to travel the first 75m?

Answer 1

To find the time taken to travel the first 75 meters, we need to break down the motion into two parts: the acceleration phase and the constant speed phase.

1. Acceleration Phase: The car accelerates uniformly from rest to a speed of 0.6 m/s^2 for 11 seconds. To find the distance covered during this phase, we can use the formula:

$d=\frac{1}{2}a{t}^2$

Where: d = distance covered a = acceleration t = time

Substituting the values: $d=\frac{1}{2}\times 0.6{\text{m/s}}^2\times (11\text{s}{)}^2$ $d=\frac{1}{2}\times 0.6{\text{m/s}}^2\times 121{\text{s}}^2$ $d=0.3{\text{m/s}}^2\times 121{\text{s}}^2$ d=36.3 md = 36.3 , ext{m}<span clas