To calculate the number of grams of magnesium sulfate dissolved in a solution, we need to use the formula:
Mass (in grams) = Molarity (in moles/L) * Volume (in L) * Molar mass (in g/mol)
Given: Molarity (M) = 0.0575 M Volume (V) = 0.965 L Molar mass of magnesium sulfate (MgSO₄) = 120.36 g/mol
First, let's calculate the number of moles of magnesium sulfate:
Moles = Molarity * Volume Moles = 0.0575 M * 0.965 L Moles ≈ 0.05548 mol
Now, we can calculate the mass using the moles and molar mass:
Mass = Moles * Molar mass Mass = 0.05548 mol * 120.36 g/mol Mass ≈ 6.674 g
Therefore, approximately 6.674 grams of magnesium sulfate are dissolved in 0.965 L of the 0.0575 M solution.