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According to the theory of special relativity, the mass of a particle increases as its velocity approaches the speed of light. The relationship between the rest mass (m₀) of a particle and its relativistic mass (m) at a given velocity (v) can be expressed by the equation:

m = γ * m₀

where γ (gamma) is the Lorentz factor given by:

γ = 1 / sqrt(1 - (v²/c²))

In this equation, c represents the speed of light in a vacuum.

Given that the mass (m) of the particle is equal to four times its rest mass (m₀), we can write:

4 * m₀ = γ * m₀

Dividing both sides by m₀, we have:

4 = γ

Squaring both sides, we get:

16 = γ²

Solving for γ, we find:

γ = 4

Substituting this value back into the Lorentz factor equation, we have:

4 = 1 / sqrt(1 - (v²/c²))

Squaring both sides and rearranging the equation, we get:

1 - (v²/c²) = 1/16

(v²/c²) = 15/16

Taking the square root of both sides and simplifying, we find:

v/c = sqrt(15) / 4

Therefore, the particle is moving at a speed equal to (sqrt(15) / 4) times the speed of light (c).

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