To calculate the number of committees that can be formed consisting of two chemists and one physicist from a group of 4 chemists and 3 physicists, we can use combinatorics.
The number of ways to choose 2 chemists from 4 is given by the combination formula:
C(4, 2) = 4! / (2!(4-2)!) = 6
Similarly, the number of ways to choose 1 physicist from 3 is:
C(3, 1) = 3! / (1!(3-1)!) = 3
Since we need to choose 2 chemists and 1 physicist, we can multiply these two values together:
6 * 3 = 18
Therefore, there are 18 different committees that can be formed consisting of two chemists and one physicist from the given group.