To find the time taken for the liquid to cool to 25°C, we need to substitute T = 25°C into the equation and solve for x.
The equation given is: T = 80(0.88)^x
Substituting T = 25, we have: 25 = 80(0.88)^x
To solve for x, we can divide both sides of the equation by 80: 0.3125 = (0.88)^x
Now, let's take the logarithm (base 0.88) of both sides to isolate x: log(0.3125) / log(0.88) = x
Using a calculator, we can evaluate the logarithms to find x: x ≈ 6.115
Therefore, the time taken for the liquid to cool to 25°C is approximately 6.115 minutes.