To solve this problem, we can use Charles's law, which states that the volume of an ideal gas is directly proportional to its temperature when pressure is held constant.
Charles's law can be expressed as:
V1T1=V2T2frac{{V_1}}{{T_1}} = frac{{V_2}}{{T_2}}T1V1=T2V2
where:
- V1V_1V1 is the initial volume of the gas,
- T1T_1T1 is the initial temperature of the gas,
- V2V_2V2 is the final volume of the gas (which we need to find),
- T2T_2T2 is the final temperature of the gas.
Given:
- V1=1.2 litresV_1 = 1.2 , ext{litres}V1=1.2litres
- T1=20 °C=20+273.15 KT_1 = 20 , degree ext{C} = 20 + 273.15 , ext{K}T<span class