To solve this problem, we can use the combined gas law, which relates the initial and final states of a gas sample when pressure, volume, and temperature change. The combined gas law equation is as follows:
(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂
Where: P₁ = Initial pressure V₁ = Initial volume T₁ = Initial temperature P₂ = Final pressure V₂ = Final volume T₂ = Final temperature
Given: Initial volume (V₁) = 220 ml Initial temperature (T₁) = Standard Temperature and Pressure (STP) = 273 K Final temperature (T₂) = 340 K Final pressure (P₂) = 1.05 ATM
We need to find the final volume (V₂).
Using the given values, we can rearrange the combined gas law equation to solve for V₂:
V₂ = (P₁ * V₁ * T₂) / (P₂ * T₁)
Substituting the given values into the equation:
V₂ = (1 * 220 * 340) / (1.05 * 273)
V₂ ≈ 267.93 ml
Therefore, the volume of the gas at a temperature of 340 K and a pressure of 1.05 ATM would be approximately 267.93 ml.