To calculate the resulting pressure when the temperature is changed from 22.0°C to 0°C, we can use the combined gas law, which states:
(P1 × V1) / (T1) = (P2 × V2) / (T2)
Where: P1 = Initial pressure (745.0 mm Hg) V1 = Initial volume (assuming constant) T1 = Initial temperature (22.0°C + 273.15 = 295.15 K) P2 = Final pressure (unknown) V2 = Final volume (assuming constant) T2 = Final temperature (0°C + 273.15 = 273.15 K)
Plugging in the values into the equation, we have:
(745.0 mm Hg × V1) / 295.15 K = (P2 × V2) / 273.15 K
Since the volume is assumed to be constant, V1/V2 cancels out:
745.0 mm Hg / 295.15 K = P2 / 273.15 K
Now, rearranging the equation to solve for P2:
P2 = (745.0 mm Hg / 295.15 K) × 273.15 K
P2 ≈ 689.2 mm Hg
Therefore, the resulting pressure when the temperature is changed from 22.0°C to 0°C is approximately 689.2 mm Hg.