To solve this problem, we can use the ideal gas law, which states:
PV = nRT
Where: P = Pressure V = Volume n = Number of moles of gas R = Ideal gas constant T = Temperature
Since we are comparing the pressure of the gas in two different volumes at the same temperature, we can set up the following equation:
P1V1 = P2V2
Where: P1 = Initial pressure (44 ATM) V1 = Initial volume (8 L) P2 = Final pressure (unknown) V2 = Final volume (55 L)
We can rearrange the equation to solve for P2:
P2 = (P1 * V1) / V2
Plugging in the values:
P2 = (44 ATM * 8 L) / 55 L
P2 = 6.4 ATM
Therefore, the gas would exert a pressure of 6.4 ATM in a 55 L tank at the same temperature.