Question

Water of mass 400g at 30°C is mixed with 200g of water at 80°C. Neglecting heat losses, what is the temperature of the mixture?

Answer 1

To find the final temperature of the mixture, we can use the principle of conservation of energy, assuming no heat losses to the surroundings. The equation used is:

$m_1{c}_1{T}_1+m_2{c}_2{T}_2=(m_1+m_2)c_{\text{mix}}{T}_{\text{mix}}$

where $m_1$ and $m_2$ are the masses of the two substances (in grams), $c_1$ and $c_2$ are the specific heat capacities of the substances (in J/g°C), T1T_1<span class="katex-html" aria-hidden="