To find the absolute temperature of the gas, we can use the ideal gas law equation:
PV = nRT
Where: P = pressure (in atmospheres) V = volume (in liters) n = number of moles of gas R = ideal gas constant (0.0821 L·atm/(mol·K)) T = absolute temperature (in Kelvin)
Rearranging the equation to solve for temperature:
T = PV / (nR)
Substituting the given values into the equation:
P = 0.933 ATM V = 10.0 L n = 0.118 mol R = 0.0821 L·atm/(mol·K)
T = (0.933 ATM) * (10.0 L) / (0.118 mol * 0.0821 L·atm/(mol·K))
T = 79.23 K
Therefore, the absolute temperature of 0.118 mol of gas that occupies 10.0 L at 0.933 ATM is 79.23 Kelvin.