To calculate the amount of heat required to vaporize a given mass of water, we need to use the heat of vaporization and the molar mass of water.
First, let's calculate the number of moles of water in 80.6 g. The molar mass of water (H₂O) is approximately 18.015 g/mol.
Number of moles of water = Mass of water / Molar mass of water Number of moles of water = 80.6 g / 18.015 g/mol ≈ 4.479 mol
Now, we can calculate the heat required to vaporize this amount of water using the heat of vaporization.
Heat required = Number of moles of water × Heat of vaporization Heat required = 4.479 mol × 40.7 kJ/mol ≈ 182.353 kJ
Therefore, approximately 182.353 kilojoules (kJ) of heat are required to vaporize 80.6 grams of water at 100 degrees Celsius, assuming the heat of vaporization of water at 100 degrees Celsius is 40.7 kJ/mol.