+3 votes
in Thermodynamics by
edited by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
+1 vote
by

To calculate the enthalpy of vaporization of benzene at the vaporization temperature, you can use the following equation:

ΔH_vap = ΔH_fus + ΔH_vap_gas - ΔH_fus_gas

where: ΔH_vap is the enthalpy of vaporization ΔH_fus is the enthalpy of fusion ΔH_vap_gas is the standard enthalpy of vaporization of the gas phase benzene ΔH_fus_gas is the standard enthalpy of fusion of the gas phase benzene

To calculate the enthalpy of vaporization, you need the heat capacity of liquid benzene (Cp_liquid), the heat capacity of gaseous benzene (Cp_gas), the temperature of vaporization (T_vap), and the standard enthalpy of formation of liquid and gaseous benzene (ΔH_fus and ΔH_fus_gas) at 298 K.

The enthalpy of fusion (ΔH_fus) is given by:

ΔH_fus = Cp_liquid * (T_vap - 298 K)

The standard enthalpy of vaporization of the gas phase (ΔH_vap_gas) is given by:

ΔH_vap_gas = Cp_gas * (T_vap - 298 K)

The standard enthalpy of fusion of the gas phase (ΔH_fus_gas) is given by:

ΔH_fus_gas = ΔH_fus + ΔH_vap_gas

Finally, you can substitute these values into the first equation to calculate the enthalpy of vaporization (ΔH_vap).

Note: Make sure the units for temperature and heat capacity are consistent (e.g., Kelvin and Joules).

Welcome to Physicsgurus Q&A, where you can ask questions and receive answers from other members of the community.
...