To solve this problem, we can use the combined gas law, which relates the initial and final conditions of temperature, pressure, and volume for a gas. The combined gas law equation is as follows:
(P₁ * V₁) / (T₁) = (P₂ * V₂) / (T₂)
Where: P₁ is the initial pressure (standard pressure at STP = 1 atm) V₁ is the initial volume (220 ml) T₁ is the initial temperature (standard temperature at STP = 273.15 K) P₂ is the final pressure (1.05 atm) V₂ is the final volume (unknown) T₂ is the final temperature (340 K)
We can rearrange the equation to solve for V₂:
V₂ = (P₁ * V₁ * T₂) / (P₂ * T₁)
Now we substitute the given values:
V₂ = (1 atm * 220 ml * 340 K) / (1.05 atm * 273.15 K)
V₂ ≈ 230.34 ml
Therefore, the volume of the gas, when its temperature is 340 K and pressure is 1.05 atm, would be approximately 230.34 ml.