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To calculate the amount of energy transferred to the water, you can use the specific heat capacity formula:

Q = m * c * ΔT

Where: Q is the energy transferred (in joules), m is the mass of the water (in kilograms), c is the specific heat capacity of water (in joules per kilogram per degree Celsius), ΔT is the change in temperature (in degrees Celsius).

The specific heat capacity of water is approximately 4.18 joules per gram per degree Celsius, or 4,180 joules per kilogram per degree Celsius.

Converting the mass of water from 1.3 kg to grams: 1 kg = 1000 grams 1.3 kg = 1.3 * 1000 grams = 1300 grams

Now we can calculate the energy transferred:

ΔT = 100°C - 20°C = 80°C

Q = 1300 grams * 4.18 joules/gram/°C * 80°C = 1300 * 4.18 * 80 joules ≈ 431,840 joules

Therefore, approximately 431,840 joules of energy were transferred to the water.

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