Standard Temperature and Pressure (STP) is defined as a temperature of 0 degrees Celsius (273.15 Kelvin) and a pressure of 1 atmosphere (760 mmHg or 101.3 kilopascals).
To find the volume of the gas at STP, we can use the combined gas law, which relates the initial and final conditions of a gas sample. The combined gas law is expressed as:
(P₁ * V₁) / (T₁) = (P₂ * V₂) / (T₂)
Where P₁, V₁, and T₁ represent the initial pressure, volume, and temperature, and P₂, V₂, and T₂ represent the final pressure, volume, and temperature.
Given: P₁ = 1000 mmHg V₁ = 480 ml T₁ = 40°C = 40 + 273.15 = 313.15 K (temperature in Kelvin)
Let's plug in the values into the combined gas law equation:
(1000 mmHg * 480 ml) / (313.15 K) = (1 atm * V₂) / (273.15 K)
Simplifying the equation:
(1000 mmHg * 480 ml * 273.15 K) / (313.15 K) = 1 atm * V₂
To find V₂, we divide both sides of the equation by 1 atm:
V₂ = (1000 mmHg * 480 ml * 273.15 K) / (313.15 K)
V₂ ≈ 404.81 ml
Therefore, at standard temperature and pressure (STP), the gas occupies approximately 404.81 ml of volume.