To determine which element in the periodic table has an average atomic mass that is about ten times that of fluorine, we can compare the atomic masses of fluorine (F) and other elements.
The atomic mass of fluorine (F) is approximately 19 atomic mass units (AMU).
To find an element with an average atomic mass about ten times that of fluorine, we can multiply the atomic mass of fluorine by ten: 19 AMU x 10 = 190 AMU.
Based on the periodic table, the element with an atomic mass close to 190 AMU is gold (Au), which has an atomic mass of approximately 197 AMU. Therefore, gold (Au) is an element whose average atomic mass is about ten times that of fluorine.