To determine the mass of sodium that contains the same number of atoms as 27 grams of aluminum, we need to compare the molar masses of the two elements.
The molar mass of aluminum (Al) is approximately 26.98 grams per mole, which means that 27 grams of aluminum is equal to 1 mole of aluminum atoms.
The molar mass of sodium (Na) is approximately 22.99 grams per mole. Since we want to find the mass of sodium that contains the same number of atoms as 27 grams of aluminum (1 mole), we need to calculate the mass of sodium that corresponds to 1 mole of sodium atoms.
To find the mass of sodium, we can set up a proportion using the molar masses:
(1 mole of aluminum) / (27 grams of aluminum) = (1 mole of sodium) / (x grams of sodium)
Using the proportion, we can solve for x:
x = (1 mole of sodium) / [(1 mole of aluminum) / (27 grams of aluminum)] = (1 mole of sodium) * (27 grams of aluminum) / (1 mole of aluminum) = 27 grams of sodium
Therefore, the mass of sodium that contains the same number of atoms as 27 grams of aluminum is also 27 grams.