When you throw a ball straight up in the air, it briefly stops at the highest point of its trajectory before starting to descend. This point is known as the peak or the apex of the ball's flight. The duration of this pause depends on various factors such as the initial velocity, air resistance, and gravitational acceleration.
Assuming there is no significant air resistance, we can consider the motion of the ball under the influence of gravity alone. In this case, the time it takes for the ball to reach its highest point and start descending again is equal to half of the total time it takes for the entire motion (going up and coming back down).
The total time in the air can be calculated using the following formula: t=2v0gt = frac{2v_0}{g}t=g2v0 where:
- ttt represents the total time in the air,
- v0v_0v0 is the initial velocity of the ball, and
- ggg is the acceleration due to gravity (approximately 9.8 m/s² on Earth).
Therefore, the time the ball stops at its peak before starting to go down is half of ttt, or t2frac{t}{2}2t.
Keep in mind that in reality, factors such as air resistance and the actual release angle may influence the exact duration of the pause, but in a simplified scenario, this is the general principle.