To calculate the mass of silver that can be extracted from a given mass of silver bromide (AgBr), we need to consider the molar ratio between silver (Ag) and silver bromide (AgBr).
First, we need to determine the molar mass of AgBr and Ag.
Given: Atomic mass of bromide (Br) = 80 g/mol Atomic mass of silver (Ag) = 108 g/mol
The molar mass of AgBr can be calculated as follows: Molar mass of AgBr = Atomic mass of Ag + Atomic mass of Br = 108 g/mol + 80 g/mol = 188 g/mol
Now, we can calculate the number of moles of AgBr present in 564 g of AgBr by using the molar mass: Number of moles of AgBr = Mass of AgBr / Molar mass of AgBr = 564 g / 188 g/mol = 3 moles
According to the balanced chemical equation, the molar ratio between AgBr and Ag is 1:1. This means that for every 1 mole of AgBr, we can obtain 1 mole of Ag.
Therefore, the number of moles of Ag that can be extracted will be the same as the number of moles of AgBr, which is 3 moles.
Finally, we can calculate the mass of silver (Ag) that can be extracted from 564 g of silver bromide: Mass of silver (Ag) = Number of moles of Ag * Molar mass of Ag = 3 moles * 108 g/mol = 324 g
Thus, from 564 g of silver bromide, approximately 324 g of silver can be extracted.