Question

If aluminium has 3 valence electrons, then how can I calculate the number of valence electrons in 10 moles of aluminum?

Answer 1

To calculate the number of valence electrons in a given number of moles of aluminum, you need to consider the Avogadro's number and the valence electron configuration of aluminum.

Aluminum (Al) has an atomic number of 13, which means it has 13 electrons. Its electron configuration is 2-8-3, indicating that it has three valence electrons.

Avogadro's number, denoted as $N_A$, is approximately $6.022\times 10^{23}$ and represents the number of entities (atoms, molecules, etc.) in one mole of a substance.

To calculate the number of valence electrons in 10 moles of aluminum, you can use the following steps:

1. Determine the number of atoms in 10 moles of aluminum: Number of atoms = $N_A\times \text{moles}$
   Number of atoms = $6.022\times 10^{23}\times 10$
   Number of atoms = $6.022\times 10^{24}$

2. Multiply the number of atoms by the number of valence electrons per atom: Number of valence electrons = Number of atoms $\times$ Number of valence electrons per atom
   Number of valence electrons = $6.022\times 10^{24}\times 3$
   Number of valence electrons = $1.8066\times 10^{25}$

Therefore, in 10 moles of aluminum, there are approximately $1.8066\times 10^{25}$ valence electrons.