To determine the Lewis structure of CHIFBr (Carbon, Hydrogen, Iodine, Fluorine, and Bromine), we need to know the number of valence electrons each element contributes.
- Carbon (C) has 4 valence electrons.
- Hydrogen (H) has 1 valence electron.
- Iodine (I) has 7 valence electrons.
- Fluorine (F) has 7 valence electrons.
- Bromine (Br) has 7 valence electrons.
Now let's calculate the total number of valence electrons in CHIFBr:
Carbon (C): 1 atom × 4 valence electrons = 4 valence electrons Hydrogen (H): 1 atom × 1 valence electron = 1 valence electron Iodine (I): 1 atom × 7 valence electrons = 7 valence electrons Fluorine (F): 1 atom × 7 valence electrons = 7 valence electrons Bromine (Br): 1 atom × 7 valence electrons = 7 valence electrons
Total valence electrons: 4 + 1 + 7 + 7 + 7 = 26 valence electrons
To draw the Lewis structure, we start by connecting the atoms with single bonds. Carbon will be the central atom since it is least electronegative compared to the other elements.
C-H-I-F-Br
Now, we distribute the remaining valence electrons around the atoms to fulfill the octet rule (except for hydrogen, which only needs 2 electrons):