Question

A body travelling at 20 meters per second is brought to rest with a constant deceleration of 10 meter per second square. What is the distance covered?

Answer 1

To find the distance covered by the body, we can use the kinematic equation:

$v^2=u^2+2as$

Where: $v$ = final velocity (0 m/s, as the body is brought to rest) $u$ = initial velocity (20 m/s) $a$ = acceleration (deceleration) (-10 m/s², since it's acting opposite to the direction of motion) $s$ = distance covered

Substituting the given values into the equation:

$0^2=20^2+2(-10)s$

Simplifying the equation:

$0=400-20s$

Rearranging the equation to solve for $s$:

$20s=400$

$s=400/20$

$s=20$

Therefore, the distance covered by the body is 20 meters.