Question

When the brake is applied in a vehicle travelling with a velocity of 25m/s, the retardation becomes 0.5m/S. How far will it travel in 15 seconds?

Answer 1

To find the distance traveled by the vehicle when the brakes are applied, we can use the equation of motion:

$d=v_i\cdot t+\frac{1}{2}\cdot a\cdot t^2$

where $d$ is the distance traveled, $v_i$ is the initial velocity, $a$ is the retardation (negative acceleration), $t$ is the time.

Given: $v_i=25\text{m/s}$ (initial velocity) $a=-0.5{\text{m/s}}^2$ (retardation) $t=15\text{s}$ (time)

Substituting these values into the equation, we have:

d=25 m/s⋅15 s+12⋅(−0.5 m/s2)⋅(15 s)2d = 25 , ext{m/s} cdot 15 , ext{s} + frac{1}{2} cdot (-0.5 , ext{m/s}^2) cdot (15 , ext{s})^2d=25m/s⋅15s<span cl