To determine the distance the object lands from the tower and the angle of the final velocity, we need to make a few assumptions. First, we assume that there is no air resistance acting on the object. Second, we assume that the motion of the object is two-dimensional, neglecting any vertical motion.
Given: Initial velocity (u) = 8 m/s Time of flight (t) = 3.6 s
To find the horizontal distance (range) covered by the object, we can use the formula:
Range (R) = u * t
Plugging in the given values:
R = 8 m/s * 3.6 s R = 28.8 meters
Therefore, the object lands at a horizontal distance of 28.8 meters away from the tower.
To determine the angle (θ) of the final velocity, we can use the following formula:
θ = tan^(-1)(v_y / v_x)
Since there is no vertical motion, the final vertical velocity (v_y) is zero. The horizontal velocity (v_x) remains constant throughout the motion and is equal to the initial horizontal velocity (u).
θ = tan^(-1)(0 / 8 m/s) θ = tan^(-1)(0) θ = 0 degrees
Therefore, the angle of the final velocity with the horizontal is 0 degrees, indicating that the final velocity is purely horizontal.