Question

A vehicle starts to move from rest and attains an acceleration of 0.8m/s in 10 seconds. What is the final velocity and distance covered by the vehicle within that time?

Answer 1

To determine the final velocity and distance covered by the vehicle, we can use the kinematic equations of motion.

1. The first equation relates final velocity (v), initial velocity (u), acceleration (a), and time (t):

v = u + at.

Given that the initial velocity (u) is zero, we can simplify the equation:

v = at.

2. The second equation relates displacement (s), initial velocity (u), acceleration (a), and time (t):

s = ut + (1/2)at^2.

Since the initial velocity (u) is zero, the equation simplifies further:

s = (1/2)at^2.

Given the values of acceleration (a = 0.8 m/s²) and time (t = 10 s), we can now calculate the final velocity (v) and distance covered (s).

Using equation 1:

v = at = 0.8 m/s² * 10 s = 8 m/s.

The final velocity of the vehicle is 8 m/s.

Using equation 2:

s = (1/2)at^2 = (1/2) * 0.8 m/s² * (10 s)^2 = 0.8 m/s² * 100 s² = 80 m.

The distance covered by the vehicle within that time is 80 meters.