Question

An object travelling with an initial velocity of 10m/s and covers 20 m with a constant acceleration of 5m/S². What is the time taken to travel?

Answer 1

To find the time taken to travel, we can use the kinematic equation:

$s=ut+\frac{1}{2}a{t}^2$

Where:

• $s$ is the distance traveled (20 m in this case)
• $u$ is the initial velocity (10 m/s)
• $a$ is the constant acceleration (5 m/s²)
• $t$ is the time taken

Plugging in the given values, we can solve for $t$:

$20=(10)t+\frac{1}{2}(5)t^2$

Simplifying the equation:

$20=10t+\frac{5}{2}{t}^2$

Rearranging the equation:

$2t^2+10t-20=0$