Question

A bullet in a gun is accelerated from the firing chamber to the end of the barrel at an average rate of 6.20 x 105 m/^2 for 8.10 x10 ^-4 s. What is its muzzle velocity (that is, its final velocity)?

Answer 1

To find the muzzle velocity of the bullet, we can use the equation of motion:

v = u + at

Where: v = final velocity (muzzle velocity) u = initial velocity (assumed to be zero since the bullet starts from rest) a = acceleration t = time

Given: a = 6.20 x 10^5 m/s^2 t = 8.10 x 10^-4 s

Substituting the values into the equation, we have:

v = 0 + (6.20 x 10^5 m/s^2)(8.10 x 10^-4 s)

v = 5.02 x 10^2 m/s

Therefore, the muzzle velocity of the bullet is 5.02 x 10^2 m/s.