To determine the final velocity and acceleration of the car, we'll use the equations of motion.
The equation linking distance (d), initial velocity (u), final velocity (v), time (t), and acceleration (a) is:
d = ut + (1/2)at²
Given: Initial velocity (u) = 20 m/s Time (t) = 30 s Distance (d) = 1200 m
Using the above equation, we can rearrange it to solve for acceleration (a):
d = ut + (1/2)at² 1200 = (20)(30) + (1/2)a(30)² 1200 = 600 + 15a(900) 600 = 13500a a = 600 / 13500 a ≈ 0.0444 m/s²
Therefore, the acceleration of the car is approximately 0.0444 m/s².
Now, we can use another equation of motion to calculate the final velocity (v):
v = u + at
v = 20 + (0.0444)(30) v ≈ 21.333 m/s
Therefore, the final velocity of the car is approximately 21.333 m/s, and the acceleration is approximately 0.0444 m/s².