To calculate the distance covered by a car during a given time interval when starting from rest and attaining a certain velocity, you can use the equation of motion:
s = ut + (1/2)at^2
where: s is the distance covered, u is the initial velocity, t is the time taken, a is the acceleration.
In this case, the car starts from rest, so the initial velocity u is 0 m/s. The final velocity v is 20 m/s, and the time taken t is 5 s.
Since the car starts from rest, the initial velocity u is 0, so the equation simplifies to:
s = (1/2)at^2
To find the acceleration a, we can use the formula:
a = (v - u) / t
Plugging in the values:
a = (20 m/s - 0 m/s) / 5 s = 20 m/s / 5 s = 4 m/s^2
Now we can substitute the value of acceleration into the equation for distance:
s = (1/2)(4 m/s^2)(5 s)^2 = (1/2)(4 m/s^2)(25 s^2) = 2 m/s^2 * 25 s^2 = 50 m
Therefore, the distance covered by the car during this time is 50 meters.