A body moving with an initial velocity of 20 m/s has an acceleration of 4 m/s^2. Find the velocity of the moving body after 4s and distance traveled in that time?

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skiingscot · Answer 1 · 2022-02-18T10:03:25+0000

To find the velocity of the body after 4 seconds and the distance traveled in that time, we can use the following equations of motion:

Where: v = final velocity u = initial velocity a = acceleration t = time s = distance

Given: Initial velocity (u) = 20 m/s Acceleration (a) = 4 m/s^2 Time (t) = 4 seconds

To find the velocity after 4 seconds (v), we can use the first equation: v = u + at

v = 20 m/s + (4 m/s^2) * (4 s) v = 20 m/s + 16 m/s v = 36 m/s

Therefore, the velocity of the body after 4 seconds is 36 m/s.

To find the distance traveled in 4 seconds (s), we can use the second equation: s = ut + (1/2)at^2

s = (20 m/s) * (4 s) + (1/2) * (4 m/s^2) * (4 s)^2 s = 80 m + (1/2) * 4 m/s^2 * 16 s^2 s = 80 m + 32 m s = 112 m

Therefore, the distance traveled by the body in 4 seconds is 112 meters.