Question

A car travels equal distances in the same direction with velocities 60 km h–1 , 20 kmh -1 and 10 km h– 1 respectively. The magnitude of average velocity of the car over the whole journey of motion is?

Answer 1

To find the magnitude of the average velocity of the car over the entire journey, we need to calculate the total displacement and divide it by the total time taken.

Given velocities: $v_1=60\text{km/h}$, $v_2=20\text{km/h}$, $v_3=10\text{km/h}$.

To calculate the average velocity, we need to find the total displacement. Since the car travels equal distances in the same direction, the total displacement is zero. This is because the car's starting and ending points are the same.

Now, let's calculate the average velocity.

Total displacement = 0 km

Total time = time taken at $v_1$ + time taken at $v_2$ + time taken at $v_3$

We need to convert the velocities to meters per second (m/s) to match the SI unit system:

$v_1=60\text{km/h}=\frac{60\times 1000}{3600}\text{m/s}$ (1 km = 1000 m, 1 hour = 3600 s) $<span\; class="mord\; mathno$