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To calculate the velocity of the ball just before it touches the ground, we can use the equations of motion. Assuming no air resistance, we can use the equation:

v^2 = u^2 + 2as

Where: v = final velocity (unknown) u = initial velocity (0 m/s, since the ball is dropped) a = acceleration due to gravity (approximately 9.8 m/s^2) s = distance or height (50 m, since the ball is dropped from a height of 50 m)

Plugging in the values into the equation, we get:

v^2 = 0^2 + 2 * 9.8 * 50

Simplifying:

v^2 = 980

Taking the square root of both sides to solve for v:

v = √980 ≈ 31.30 m/s

Therefore, the velocity of the ball just before it touches the ground is approximately 31.30 m/s.

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