To determine the velocity of a ball just before it hits the ground after being dropped from a plane, we can use the equations of motion. Assuming no air resistance, we can use the equation:
velocity = acceleration × time
In this case, the acceleration is due to gravity and is approximately 9.8 meters per second squared (9.8 m/s^2) downward. We need to convert the time to seconds for consistent units.
Given that the time is 10 seconds, we can substitute the values into the equation:
velocity = 9.8 m/s^2 × 10 s = 98 m/s
Therefore, the velocity of the ball just before it hits the ground is approximately 98 meters per second.