To calculate the percentage of pure phosphorus (P) in Ammonium phosphate (APP) with the formula 11-48-0, we need to determine the molecular mass of APP and then find the percentage of P in it.
The molecular formula of Ammonium phosphate (APP) is (NH₄)₃PO₄. Let's calculate its molecular mass:
The atomic mass of nitrogen (N) = 14 The atomic mass of hydrogen (H) = 1 The atomic mass of phosphorus (P) = 31 The atomic mass of oxygen (O) = 16
Now, we can calculate the molecular mass of (NH₄)₃PO₄:
Molecular mass of (NH₄)₃PO₄ = (3 × atomic mass of NH₄) + atomic mass of PO₄
= (3 × (atomic mass of N + 4 × atomic mass of H)) + (atomic mass of P + 4 × atomic mass of O)
= (3 × (14 + 4 × 1)) + (31 + 4 × 16)
= (3 × 18) + (31 + 64)
= 54 + 95
= 149
So, the molecular mass of (NH₄)₃PO₄ is 149 g/mol.
Next, let's calculate the percentage of pure phosphorus (P) in APP:
Percentage of pure phosphorus (P) = (Molar mass of P / Molar mass of (NH₄)₃PO₄) × 100
= (31 / 149) × 100
≈ 20.8%
Therefore, the percentage of pure phosphorus (P) in Ammonium phosphate (APP) is approximately 20.8%.