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The velocity of a projectile upon reaching the ground depends on various factors, such as the initial velocity, launch angle, air resistance, and the height from which it was launched. Assuming we neglect air resistance and consider a projectile launched horizontally, the vertical component of the velocity will be influenced by the acceleration due to gravity.

When a projectile reaches the ground, its vertical velocity component will be determined by the time it takes to fall and the acceleration due to gravity. Assuming the projectile was launched from rest, we can calculate the time it takes to reach the ground using the equation:

Distance = (1/2) * acceleration * time^2

Since the projectile was launched horizontally, its initial vertical velocity is zero. Thus, the distance fallen is equal to the height from which it was launched. Rearranging the equation, we have:

Height = (1/2) * acceleration * time^2

Solving for time:

time = sqrt((2 * Height) / acceleration)

Substituting the value of the acceleration due to gravity (approximately 9.8 m/s^2) and the height from which the projectile was launched, we can find the time it takes to reach the ground.

Once we have the time, we can determine the final vertical velocity using:

Final vertical velocity = acceleration * time

Since the projectile was launched horizontally, the horizontal velocity component remains constant throughout its trajectory. Therefore, the velocity of the projectile on reaching the ground would have a horizontal component equal to the initial horizontal velocity and a vertical component equal to the final vertical velocity.

Keep in mind that these calculations assume idealized conditions and neglect factors like air resistance, which can influence the actual velocity of a projectile upon reaching the ground in real-world situations.

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