Question

A vehicle starts to move from rest and attains an acceleration of 0.8 m/s in 10 seconds. What is the final velocity and distance covered by the vehicle within that time?

Answer 1

To find the final velocity and distance covered by the vehicle, we can use the following equations of motion:

1. Final velocity (v) = Initial velocity (u) + Acceleration (a) * Time (t)
2. Distance (s) = Initial velocity (u) * Time (t) + (1/2) * Acceleration (a) * Time (t)^2

Given: Initial velocity (u) = 0 m/s (starting from rest) Acceleration (a) = 0.8 m/s² Time (t) = 10 seconds

Using equation (1), we can calculate the final velocity:

v = u + a * t v = 0 m/s + 0.8 m/s² * 10 s v = 0 m/s + 8 m/s v = 8 m/s

The final velocity of the vehicle after 10 seconds is 8 m/s.

Now, using equation (2), we can calculate the distance covered:

s = u * t + (1/2) * a * t^2 s = 0 m/s * 10 s + (1/2) * 0.8 m/s² * (10 s)^2 s = 0 m + (1/2) * 0.8 m/s² * 100 s² s = 0 m + 0.4 m/s² * 100 s² s = 0 m + 40 m s = 40 m

The vehicle covers a distance of 40 meters within the 10-second time interval.