Question

A car starts with a velocity of 10m/s and accelerates at a rate of 5m/s×s. How would one find the final velocity when the car has travelled a distance of 30m?

Answer 1

To find the final velocity of the car when it has traveled a distance of 30 meters, we can use the following kinematic equation:

$v^2=u^2+2as$

where:

• $v$ is the final velocity
• $u$ is the initial velocity
• $a$ is the acceleration
• $s$ is the distance traveled

Given: $u=10\text{m/s}$ (initial velocity) $a=5{\text{m/s}}^2$ (acceleration) $s=30\text{m}$ (distance traveled)

We can rearrange the equation to solve for $v$:

$v^2=u^2+2as$

v2=(10 m/s)2+2⋅5 m/s2⋅30 mv^2 = (10 , ext{m/s})^2 + 2 cdot 5 , ext{m/s}^2 cdot 30 , ext{m}v2=(10m/s)2+2⋅5<span