A car moving in the positive direction with an initial velocity of 32 m/s slows down at a constant rate of -3 m/s2. What is its velocity in meters/second after 8 seconds of deceleration?

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James · Answer 1 · 2023-01-23T10:03:25+0000

To find the final velocity of the car after 8 seconds of deceleration, we can use the following equation:

Final velocity = Initial velocity + (Acceleration * Time)

Given: Initial velocity (u) = 32 m/s (positive direction) Acceleration (a) = -3 m/s^2 (negative because it is deceleration) Time (t) = 8 seconds

Plugging in the values into the equation, we get:

Final velocity = 32 m/s + (-3 m/s^2 * 8 seconds) Final velocity = 32 m/s - 24 m/s Final velocity = 8 m/s

Therefore, the velocity of the car after 8 seconds of deceleration is 8 m/s.