To determine the mass of 3.75 x 10^21 atoms of iron, we need to know the atomic mass of iron. The atomic mass of iron is approximately 55.845 grams per mole.
We can use this information to calculate the mass of 3.75 x 10^21 atoms of iron as follows:
1 mole of iron contains Avogadro's number (6.022 x 10^23) of atoms. Therefore, the molar mass of iron (55.845 grams/mole) represents the mass of one mole of iron atoms.
To find the mass of 3.75 x 10^21 atoms, we can set up the following proportion:
(3.75 x 10^21 atoms) / (6.022 x 10^23 atoms/mole) = x grams / (55.845 grams/mole)
Simplifying the proportion, we find:
x = (3.75 x 10^21 atoms * 55.845 grams/mole) / (6.022 x 10^23 atoms/mole)
Evaluating this expression, we get:
x ≈ 0.3474 grams
Therefore, the mass of 3.75 x 10^21 atoms of iron is approximately 0.3474 grams.