To determine the time it takes for the stone to hit the ground when falling from a cliff, we can use the laws of motion and the equation for free fall. Assuming there is no air resistance, the stone will experience constant acceleration due to gravity.
The equation for the distance covered during free fall is given by:
h = (1/2) * g * t^2
Where: h is the height of the cliff g is the acceleration due to gravity (approximately 9.8 m/s^2) t is the time taken
In this case, we want to find the time it takes for the stone to hit the ground when falling from the same height as when it hits the ground below. Let's call this height 'h'.
Using the equation for distance covered during free fall, we can rewrite it as:
h = (1/2) * g * t^2
Rearranging the equation to solve for time, we get:
t^2 = (2 * h) / g
Taking the square root of both sides, we have:
t = √[(2 * h) / g]
Since the height 'h' is the same in both scenarios, the time it takes for the stone to hit the ground above will be the same as the time it takes for the stone to hit the ground below.
Therefore, the time it takes for the stone to hit the ground above will also be:
t = √[(2 * h) / g]
Note that the initial velocity of 60 m/s is not needed to determine the time of fall, as it only affects the final velocity upon impact.