To find the horizontal component of the velocity vector when the ball is landing on the ground again, we need to consider the initial velocity and the angle of projection.
Given: Initial velocity (v0) = 18.0 meters per second Launch angle (θ) = 24 degrees
The horizontal component of the velocity (v_x) can be calculated using the equation:
v_x = v0 * cos(θ)
where cos(θ) is the cosine of the launch angle.
Let's calculate the horizontal component:
v_x = 18.0 * cos(24°)
Using a calculator or trigonometric table, we find:
v_x ≈ 18.0 * 0.9135
v_x ≈ 16.44 meters per second
Therefore, the horizontal component of the velocity vector when the ball is landing on the ground again is approximately 16.44 meters per second.