Question

How far does a car travel in 6 seconds if its velocity is 2 meters and its acceleration is 2 meter squared in forward direction?

Answer 1

To determine the distance traveled by the car in 6 seconds, we can use the kinematic equation:

$d=v_{0}t+\frac{1}{2}a{t}^2$

where: $d$ is the distance traveled, $v_0$ is the initial velocity, $t$ is the time, and $a$ is the acceleration.

In this case, the initial velocity ($v_0$) is given as 2 meters per second, the time ($t$) is 6 seconds, and the acceleration ($a$) is 2 meters per second squared.

Substituting the given values into the equation, we have:

$d=(2\text{m/s})(6\text{s})+\frac{1}{2}(2{\text{m/s}}^2)(6\text{s}{)}^2$

Simplifying:

d=12 m+12(2 </