Question

A car starts from rest and has a velocity of 15 kph in 2 seconds. What are the acceleration and distance traveled by the car?

Answer 1

To find the acceleration and distance traveled by the car, we can use the equations of motion.

Given: Initial velocity ($u$) = 0 kph (since the car starts from rest) Final velocity ($v$) = 15 kph Time ($t$) = 2 seconds

First, let's convert the velocities to meters per second (m/s) since the equations of motion require the use of SI units:

Initial velocity ($u$) = 0 kph = 0 m/s Final velocity ($v$) = 15 kph = 15 * (1000/3600) m/s ≈ 4.17 m/s Time ($t$) = 2 seconds

The first equation of motion relates acceleration ($a$), initial velocity ($u$), final velocity ($v$), and time ($t$): $v=u+at$

Substituting the known values: 4.17 m/s = 0 m/s + a * 2 s

Simplifying the equation: 4.17 m/s = 2a

Solving for acceleration ($a$): $a=\frac{4.17\text{m/s}}{2\text{s}}$ $a\approx 2.085{\text{m/s}}^2$

The acceleration of the car is approximately $2.085{\text{m/s}}^2$.

To find the distance traveled ($d$), we can use the second equation of motion: d=ut+12at2d = ut + frac{1}{2}at^2<span class="strut"