Question

A tractor of mass 1500 kg accelerates uniformly from rest and attains a velocity of 20 m/s in 10 minutes. What is the acceleration, distance covered, and net force acting on the tractor as it accelerates?

Answer 1

To solve this problem, we can use the following equations of motion:

1. The equation for uniform acceleration: v = u + at

2. The equation for distance covered with uniform acceleration: s = ut + (1/2)at^2

where: v = final velocity u = initial velocity (0 m/s, since the tractor starts from rest) a = acceleration (to be determined) t = time (10 minutes = 600 seconds) s = distance covered (to be determined)

First, let's find the acceleration (a):

v = u + at 20 m/s = 0 + a * 600 s a = 20 m/s / 600 s a ≈ 0.0333 m/s²

Now, let's find the distance covered (s):

s = ut + (1/2)at^2 s = 0 * 600 + (1/2) * 0.0333 * (600)^2 s ≈ 599.4 meters

Finally, let's calculate the net force acting on the tractor as it accelerates. We can use Newton's second law of motion:

F = ma

F = 1500 kg * 0.0333 m/s² F ≈ 49.95 N

Therefore:

• The acceleration of the tractor is approximately 0.0333 m/s².
• The distance covered by the tractor is approximately 599.4 meters.
• The net force acting on the tractor as it accelerates is approximately 49.95 N.