+264 votes
in Velocity physics by
edited by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
+176 votes
by

To solve this problem, we can use the equation of motion:

v = u + at,

where: v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken.

Given: u = 60 km/h = 60,000 m/3,600 s = 16.67 m/s, a = 5 m/s², v = 10 m/s.

Plugging in these values into the equation of motion:

10 m/s = 16.67 m/s + 5 m/s² * t.

Rearranging the equation:

10 m/s - 16.67 m/s = 5 m/s² * t,

-6.67 m/s = 5 m/s² * t.

Dividing both sides by 5 m/s²:

t = -6.67 m/s / 5 m/s²,

t = -1.334 s.

The time taken to reach a velocity of 10 m/s is -1.334 seconds. However, a negative time value does not make physical sense in this context. It seems there might be an error or inconsistency in the given information or calculations. Please double-check the values provided or clarify any additional details if available.

Welcome to Physicsgurus Q&A, where you can ask questions and receive answers from other members of the community.
...