The distance a bullet will travel through a wall is influenced by various factors, including its initial velocity, the material and thickness of the wall, and the bullet's mass and shape. However, assuming all other factors remain constant, we can make a general approximation based on the assumption that the distance traveled is directly proportional to the velocity.
Let's say the initial velocity of the bullet is v1, and it penetrates a wall for a distance of d1 (3m in this case). If we double the velocity to v2 (2 * v1), we can estimate the new distance traveled, denoted as d2.
Based on the assumption that distance is directly proportional to velocity, we can set up the following proportion:
(v1 / d1) = (v2 / d2)
To solve for d2, we can rearrange the equation as follows:
d2 = (d1 * v2) / v1
Plugging in the given values, where d1 = 3m, and doubling the velocity implies v2 = 2 * v1, we have:
d2 = (3 * (2 * v1)) / v1 = (6 * v1) / v1 = 6
Therefore, if we double the velocity of the bullet, it is estimated to travel approximately 6 meters through the wall. Please note that this is a simplified approximation and may not hold true in all real-world scenarios, where other factors come into play.