Yes, I can help you calculate the speed of the object when it hits the ground and the height of the tower using basic equations of motion.
Let's start with the equation of motion for the vertical motion of the falling object:
h = ut + (1/2)gt^2
Where: h is the height of the tower, u is the initial vertical velocity (which is 0 since the object is dropped), g is the acceleration due to gravity (approximately 9.8 m/s^2), t is the time taken (4 seconds).
Since the object is dropped, the initial vertical velocity is zero (u = 0). The equation simplifies to:
h = (1/2)gt^2
We can rearrange this equation to solve for h:
h = (1/2)gt^2 2h = gt^2 h = (1/2)gt^2 h = (1/2) × 9.8 × (4)^2 h = 0.5 × 9.8 × 16 h = 78.4 meters
So, the height of the tower is approximately 78.4 meters.
To calculate the speed at which the object hits the ground, we can use the equation for final velocity:
v = u + gt
Since the object is dropped, the initial velocity (u) is 0. Plugging in the values, we get:
v = 0 + (9.8)(4) v = 39.2 m/s
Therefore, the speed of the object when it hits the ground is approximately 39.2 m/s.