To solve this problem, we can use the equations of motion for uniformly accelerated linear motion. The key equation we will need is:
s = ut + (1/2)at^2
where: s is the distance traveled, u is the initial velocity, t is the time, and a is the acceleration.
Given: Initial velocity (u) = 0 m/s (since the block starts from rest), Acceleration (a) = 2 m/s^2, and Time (t) = 2 seconds.
Let's calculate the distance traveled during the first 2 seconds:
s = ut + (1/2)at^2 s = 0 * 2 + (1/2) * 2 * (2^2) s = 0 + (1/2) * 2 * 4 s = 0 + 1 * 4 s = 4 meters
Therefore, the block will travel a distance of 4 meters during the first 2 seconds.
Now, let's find the velocity of the block at the end of the 2nd second. We can use the equation:
v = u + at
Given: Initial velocity (u) = 0 m/s (since the block starts from rest), Acceleration (a) = 2 m/s^2, and Time (t) = 2 seconds.
v = u + at v = 0 + 2 * 2 v = 0 + 4 v = 4 m/s
Therefore, the velocity of the block at the end of the 2nd second will be 4 m/s.