Question

A stone was thrown vertically upward with a velocity of 0.2m/s. How long will the stone reach the maximum height?

Answer 1

To determine the time it takes for the stone to reach its maximum height, we can use the kinematic equation:

$v=u+at$

Where:

• v is the final velocity (0 m/s at the highest point)
• u is the initial velocity (0.2 m/s, since the stone is thrown vertically upward)
• a is the acceleration due to gravity (-9.8 m/s²)
• t is the time taken

Substituting the known values into the equation:

$0=0.2-9.8t$

Solving for t:

$9.8t=0.2$ $t=\frac{0.2}{9.8}\approx 0.0204\text{seconds}$

Therefore, it takes approximately 0.0204 seconds (or about 20.4 milliseconds) for the stone to reach its maximum height.